MATH SOLVE

2 months ago

Q:
# An object is launched vertically in the air at 32.83 meters per second from a platform 10m above the ground. The height of the object above the ground (in meters) t seconds after launch is given by h(t)= -4.9t^2 + 32.83t +10 how long does it take the object to reach maximum height? What is the objects maximum height?

Accepted Solution

A:

IdkAnswer:Step-by-step explanation: