MATH SOLVE

4 months ago

Q:
# Find the center, vertices, and foci of the ellipse with equation x squared divided by four hundred plus y squared divided by two hundred and fifty six = 1

Accepted Solution

A:

To solve this problem you must apply the proccedure shown below:

1. You have that the equation of the ellipse is the following:

(x²/400)+(y²/256)=1

2. You have that:

((x-0)²/400)+((y-0)²/256)=1

3. Then, the center is:

(0,0)

4. The vertices are:

a²=400

a=√400

a=20

(-20,0)

(20,0)

b²=256

b=√256

b=16

(0,-16)

(0,16)

5. The focci is:

a²–c²=b²

√(400-256)=c

c=12

(-12,0)

(12,0)

1. You have that the equation of the ellipse is the following:

(x²/400)+(y²/256)=1

2. You have that:

((x-0)²/400)+((y-0)²/256)=1

3. Then, the center is:

(0,0)

4. The vertices are:

a²=400

a=√400

a=20

(-20,0)

(20,0)

b²=256

b=√256

b=16

(0,-16)

(0,16)

5. The focci is:

a²–c²=b²

√(400-256)=c

c=12

(-12,0)

(12,0)