For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and diameter of the circle? c) graph.
Accepted Solution
A:
Answer:a) center (2, -3)b) radius r = 3c) in the attachmentStep-by-step explanation:The standard form of an equation of a circle:[tex](x-h)^2+(y-k)^2=r^2[/tex](h, k) - centerr - radiusWe have:[tex](x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2[/tex]a) center (2, -3)b) radius r = 3c) in the attachment